The bounce of a Squash Ball Essay Example for Free

The bounce of a Squash Ball EssayHowever, some vigor is illogical as due to friction between the molecules in the production line, and the surface of the thump. 3 This is during the m where the l discover is in contact with the floor. There are really three stages here, I leave alone show them on a lower floor i) ii) iii) In i, the nut has hit the ground, and because of inertia, the ball tries to keep moving and cant because the ground beneath it is solid. This causes the ball to change to a sort of oval shape, this change of shape causes some skill to be lost as hot up and the kinetic capacity to become Elastic slide fastener. Also, the ball hitting the ground entrust cause some energy to go on as work and some will be sent through the surface as a wave. In ii, the ball is still, and has no energy opposite than Elastic Energy it is exactly between i and iii. In iii, The Elastic Energy is being converted to Kinetic Energy, and causes the ball to go from the oval shape, back to its original shape, and bounces off of the ground. The Elastic Energy in the ball is now becoming Kinetic Energy again and the reshaping of the ball causes some more energy to be lost as heat. 4 Here the ball is going back up after bouncing off of the ground.The ball has Kinetic Energy, and again some energy is lost as heat due to friction between the air and the ball. 5 At this stage, the ball is stationary in the air because gravity has prevented it from rising any further. However, the ball is not as high as it was when it was dropped this is because some energy was lost as heat. This stage links back to stage two repeatedly, until all of the energy from the ball has been lost, at which point it will become stationary on the ground. Prediction With this in mind, I am predicting that the high the ball is dropped from, the higher it will bounce (due to increased energy).However, I predict that the ball will never reach the peak it fell from because of energy which is lost as heat from friction and sound when it hits the ground. Calculating Epg The formula mgh (or Mass Gravity Height) will show the amount of Gravitational Potential Energy (Epg) the ball has at this stage. The stool of our ball was 0. 024 kg, which is constant (it doesnt change). The gravity here on Earth is 10N per kg of mass, for our ball this would mean 0. 24N, another constant. The point from which we drop the ball is a variable.Therefore to work out the Epg of the ball at any given big top we would use the formula Height. We can shorten this to 0. 006 because mass and gravity are constant. For example, if we wanted to know how much Epg the ball had when held at 1. 00 m, we would do 0. 006 1. 00, which is 0. 006. The reason for scheming Epg is so that later on the kinetic energy (Ek) of the ball can be calculating, in deviate allowing the velocity of the ball upon impact to be calculated. Method commencement exercise of all, two metre sticks were placed vertically ag ainst a wall, one above the other, creating a makeshift double-metre stick, this was held against the wall.Next, the ball was held so that the bottom of it was aligned with the height (e. g. 1. 00 m). Meanwhile, another division of the team laid on the floor, facing the metre stick. The ball was then released when the member on the floor was ready. When the ball bounced up the member on the floor noted it down. This was repeated quint times for each drop height (0. 8m, 1. 0m, 1. 2m, etc up to 2. 0m). After each drop height was through five times, the ball was heated to 40 degrees Celsius in a water bath. Our variable was the drop height of the ball. We chose the range 0. 6m 2.0m because it achieves a good set of results, while not taking too much time after dropping from each height five times. We dropped the ball five times from each height and then obtained an average to try and get a good range of results, and also to eliminate mistaken results from our graphs. Results Table Drop Height (m) Gravitational Potential Energy (J) Bounce Height (m) Speed on Impact (m/sec) ms Analysis.The results in this table show that the Epg increases when the ball is held higher up. It also shows that the ball bounces higher when the drop height is higher, and that the ball will never bounce to the same height it was dropped from. One other thing my table shows is that the higher the drop height, the higher the speed of the ball on impact with the ground. This proves e genuinelything I predicted to be correct, and also correlates with my energy transfer diagram, which is what I based my prediction on. Ball Speed Epg = Ek on impact. To work out the velocity (speed) of the ball on impact we would use the formula v=VEk.First we need to know the value of Ek which is dependant on Evaluation There are just two anomalies, they are at 1. 4m and 1. 6m, they is quite far from the line of best fit. I believe the cause was human beings error peradventure in the inaccuracy of trying to see how high the ball was in a component of a second.If I had the chance to repeat this investigation, I would improve the procedure by improving the mensuration system, perhaps by using a digital video camera to record how high the ball bounced and then playing it back frame by frame on a computer because it is very hard to see where the ball is in a fraction of a second with human eyesight. I would increase the range of results to be from 0. 2m maybe 5. 0m, because it would give a much larger range, in which perhaps the rule of the ball bouncing higher when dropped from higher would be incorrect.